Problems Removing the url from text using java

Question

I'm trying to remove url from some strings that i get from twitter. The code i use is:

test.replaceAll("http.*?\\s", ""));

The problem is that when i try there are some strings it doesn't work, for example:

String cuatro = ("#TodosPorKiKi El plan de flia solidaria No Puede exceder los 6meses. La justicia de Santa Fe lo abandonó 2 años y ahora\r\n" + 
            "Quieren hacerse los legalistas\r\n" + 
            "#Verguenza  Respete los derechos del niño @MiguelLifschitz @DataLifschitz https//t/MUY0bj2qMT");

output:

I dont`t know why for some text it works and for other doesn't

Since a url is without spaces you need to split the string to an array of words using str.split("..", ' ') and remove the element that starts with using str.startsWith("..") methodhttp:// or https:// — Omar Mneimneh
– Omar Mneimneh, Commented May 12, 2018 at 9:49
Since your regex contains \\s (whitespace) at the end, that means it won't work if the URL is at the end of input. — Patrick Parker
– Patrick Parker, Commented May 12, 2018 at 9:55

k_ssb · Accepted Answer · 2018-05-12 12:58:11Z

The .*? in your regex will look for a minimal zone, which will be none in fact, so it won't be able to find a space after, and it's not the good way to do it

You need to focus on 2 simple properties

url starts with http
url does not contain spaces

So your regex can be: http\S* (http followed by multiple non-space char)

String cuatro = ("#TodosPorKiKi El plan de flia solidaria No Puede exceder los 6meses. https//t/MUY0bj2qMT" +
            " La justicia de Santa Fe lo abandonó 2 años y ahora\r\n" +
            "Quieren hacerse los legalistas\r\n  https//t/MUY0bj2qMT" +
            "#Verguenza  Respete los derechos del niño @MiguelLifschitz @DataLifschitz https//t/MUY0bj2qMT");
String cleaned = cuatro.replaceAll("http\\S*", ""); 
System.out.println(cleaned);    // I added multiple url in the String, for you can see it remvoes all

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