i'm working with python/numpy and search in the docs but cant find the method to accomplish this
i have this two arrays and want to concatenate the elements inside the array into a second array
this is my first array
import numpy as np
a = np.array([0, 0, 0, 0, 0, 0, 0, 0],[0, 0, 0, 0, 0, 0, 0, 0])
my goal is
Output:
[[00000000], [00000000]]
the reason of this is for later transform every element of the array into hex
In [100]: a = np.array([[0, 0, 0, 0, 0, 0, 0, 0],[0, 0, 0, 0, 0, 0, 0, 0]])
In [101]: a
Out[101]:
array([[0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0]])
In [102]: a.astype(str)
Out[102]:
array([['0', '0', '0', '0', '0', '0', '0', '0'],
['0', '0', '0', '0', '0', '0', '0', '0']], dtype='<U11')
In [103]: a.astype(str).tolist()
Out[103]:
[['0', '0', '0', '0', '0', '0', '0', '0'],
['0', '0', '0', '0', '0', '0', '0', '0']]
In [104]: [''.join(row) for row in _]
Out[104]: ['00000000', '00000000']
A more concise, pure numpy version, adapted from this answer:
np.apply_along_axis(lambda row: row.astype('|S1').tostring().decode('utf-8'),
axis=1,
arr=a)
This will create an array of unicode strings with a maximum length of 8:
array(['00000000', '00000000'], dtype='<U8')
Note that this method only works if your original array (a) contains integers in range 0 <= i < 10, since we convert them to single, zero-terminated bytes with .astype('|S1').
You can try this approach:
import numpy as np
a = np.array([0, 0, 0, 0, 0, 0, 0, 0])
b = np.array([0, 0, 0, 0, 0, 0, 0, 0])
#concatenate
concat=np.concatenate((a,b))
#reshape
print(np.reshape(concat,[-1,8]))
output:
[[0 0 0 0 0 0 0 0]
[0 0 0 0 0 0 0 0]]
00000000? A string of '0' characters? An integer?a?