How to upload a file in Flask RESTful using cURL?

Question

I have written the next Resource:

from config import AWS_S3_BUCKET
from flask_api import status
from flask_restful import Resource, reqparse
from werkzeug.datastructures import FileStorage
from werkzeug.utils import secure_filename
import helpers


class FileUpload(Resource):

    def post(self):
        parse = reqparse.RequestParser()
        parse.add_argument('user_file', type=FileStorage, location='user_file')
        parse.add_argument('user_id', type=int, location='user_id')
        args = parse.parse_args()
        file = args['user_file']
        if file:
            file.filename = secure_filename(file.filename)
            url = helpers.upload_file_to_s3(file, AWS_S3_BUCKET)
            return {'url': url}, status.HTTP_201_CREATED

        return 'Invalid file', status.HTTP_400_BAD_REQUEST

After I'm trying to upload my file in cURL by this command:

curl -F '[email protected]' -F 'user_id=5' http://127.0.0.1:5000/files/new

In the debugger the endpoint is called but all fields: user_file and user_id are NoneType.
What am I doing wrong?
P.S. The recovery.fstab file is located in the home directory.

YB Yu · Accepted Answer · 2018-04-09 04:56:10Z

1

See the flask-RESTful docs.

Location argument is where req parser get the values from.

def post(self):
    parse = reqparse.RequestParser()
    parse.add_argument('user_file', type=FileStorage, location='files')
    parse.add_argument('user_id', type=int, location='args')
    ...

answered Apr 9, 2018 at 4:56

YB Yu

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