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I need to extract number from string 'iama5559348number'. Answer should do non capturing and expected output is 5559348. I am trying by doing this way print(re.search(r'([^(.*)]?[0-9]*)','iama5559348number'))but I am getting only only first letter

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  • @Simon yes, I included now Commented Mar 11, 2018 at 0:31

2 Answers 2

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You can use re.findall that way:

x= re.findall(r'[0-9]+','iama5559348number')[0]
print(x)

or that:

x= re.findall(r'\d+','iama5559348number')[0]
print(x)
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5 Comments

Can you answer by using non capturing group for the letters 'iama'
@AdityaMatturi: added one case else
(?!:iama)\d+ but it doesn't need at all
yeah, but I wanted more practice on non capturing. Just figuring out how to do with it
(?!:iama)\d+?(?=number) or (?!:iama)\d*?(?=number) without +, or else (?!:\D*)\d*?(?=\D*$)
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>>> print(re.search(r'([0-9]+)','iama5559348number').groups()[0])
'5559348'

or

>>> print(re.search(r'(\d+)','iama5559348number').groups()[0])
'5559348'
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2 Comments

I appreciate your answer but can you use non capturing group(?:) or [^ ] and also use '*' instead of '+' in the answer
Just dunno how to do it without capture

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