Storing pointers in multi-dimensional array

Question

My intention is to create a dynamic 3D array in C++ using pointers.

MyType*** myArray;
myArray = new MyType**[GRID_SIZE];
for (int i = 0; i < GRID_SIZE; ++i) {
  myArray[i] = new MyType*[GRID_SIZE];
  for (int j = 0; j < GRID_SIZE; ++j) {
    myArray[i][j] = new MyType[GRID_SIZE];
  }
}

Now this 3D array is ready to store MyType instances. What is the correct syntax needed when declaring this array if I want to store pointers to MyType instead of just MyType objects in this array?

IMO, this is poor idea. See the code in: stackoverflow.com/questions/2216017/… for an alternative. — Jerry Coffin
– Jerry Coffin, Commented Feb 5, 2011 at 23:22
In C++, you should almost always prefer the safety of std::vector<T> to manually managing memory. — Seth Johnson
– Seth Johnson, Commented Feb 5, 2011 at 23:24
@SethJohnson I agree wholeheartedly, but I'm modifying old code and rewriting everything is not an option. — sdfqwerqaz1
– sdfqwerqaz1, Commented Feb 6, 2011 at 14:31

BlackBear · Accepted Answer · 2011-02-05 23:22:53Z

3

Simply add another * to your declaration, but don't call new on it.

answered Feb 5, 2011 at 23:22

BlackBear

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2 Comments

sdfqwerqaz1 Over a year ago

I was of course absolutely sure that I had done that and that it didn't work. Well, I tried again and now it worked so I was obviously doing something crazy the first time. This is my dumbest question to date. I'll go and stand in the corner now.

BlackBear Over a year ago

@sdfqwerqaz: pointers are a mess. Me neither was sure it would work.. ;)

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