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I'm want to apply a regex on a string like this word in $ctrl.words Want to find if the string has in and one string after and one before.

I try with this regex [a-zA-Z\\d]+\\s+in\\s+[a-zA-Z\\d]+', but the problem are the special characters from $ctrl.words, the regex always return false. The result what i want is true for string like this fruit in $ctrl.fruits letter in $ctrl.alphabet

And false for strings like fruit in $ctrl.fruits anything else letter in $ctrl.alphabet anithing else

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    Use /^\S+\s+in\s+\S+$/. Commented Mar 1, 2018 at 18:18
  • What do you mean if the string has in and "one string after and one before?" Do you mean that there needs to be characters before and after the in - as separate words? Does the in need to have spaces around it? Commented Mar 1, 2018 at 18:18
  • Yes i'm need separate words before and after the in, and need have spaces too Commented Mar 1, 2018 at 18:21
  • Why are you escaping your backslashes? [a-zA-Z\\d] for example matches alphabetical characters, \, and d (redundantly) Commented Mar 1, 2018 at 18:23
  • 1
    @PatrickRoberts Backslashes should be doubled in RegExp constructor notation, when regex delimiters are not used. Commented Mar 1, 2018 at 18:24

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Since you need to match a string that only consists of two non-whitespace char chunks separated with in enclosed with whitespaces, you may use

/^\S+\s+in\s+\S+$/

See the regex demo

Details

  • ^ - start of string
  • \S+ - `+ non-whitespace chars
  • \s+in\s+ - an in substring enclosed with 1 or more whitespaces
  • \S+ - `+ non-whitespace chars
  • $ - end of string.

JS demo:

var strs = ['fruit in $ctrl.fruits', 'letter in $ctrl.alphabet', 'fruit in $ctrl.fruits anything else', 'letter in $ctrl.alphabet anithing else' ];
var rx = /^\S+\s+in\s+\S+$/;
for (var s of strs) {
  console.log(s, "=>", rx.test(s));
}

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