Finding the square of an unknown variable using a for loop

Question

I am trying to figure out how to find the square root for an unknown variable using a for loop. the prompt I was given is: So if we passed in 3, you would output 0^2+1^2+2^2+3^2=14

this is for my intro to scripting class, and I am just at a compete loss.

your question heading says square, and the start of question says square root and your example belongs to something else. What exactly do you want? — Moinuddin Quadri
– Moinuddin Quadri, Commented Jan 27, 2018 at 19:24
for your given example, you can get desired result using sum((n+1)**2 for i in range(n)) where n = 3 for your case — Moinuddin Quadri
– Moinuddin Quadri, Commented Jan 27, 2018 at 19:27

be_good_do_good · Accepted Answer · 2018-01-27 19:36:35Z

2

One way to do this is:

n = int(raw_input("Enter number")) # get the number, use input if you are using python 3.x
sum([i**2 for i in range(n+1)]) # form a list with squares and sum them

You can do it with lambda too. Here it goes:

reduce(lambda x,y: x + y**2, range(n+1))

edited Jan 27, 2018 at 19:36

answered Jan 27, 2018 at 19:27

be_good_do_good

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1 Comment

Moinuddin Quadri Over a year ago

also it is worth mentioning that it is raw_input for Python 2.x and input for Python 3.x

scripter · Accepted Answer · 2018-01-27 19:29:58Z

1

def solve(n):
    res = 0
    for i in range(n + 1):
        res += i ** 2
    return res

Hope that helps!

answered Jan 27, 2018 at 19:29

scripter

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2 Comments

Mast3r_Heath Over a year ago

you definitely help get me started, I had modify your code a little bit to fit the requirement by Codio (the program my school uses for coding classes). so this is what it looks like now: ( res = 0 for i in range(0, N + 1): res += i ** 2 print (res) ) the output I'm getting is 0, 1, 5. how can I get it to output a single number with the for loop?

rassa45 Over a year ago

Put the print (res) outside the for loop

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