I have a string representing a domain name. How can I get the corresponding IP address using Python 3.x? Something like this:
>>> get_ip('http://www.stackoverflow.com')
'64.34.119.12'
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2possible duplicate of How to resolve DNS in Python?Dan Grossman– Dan Grossman2011-01-27 10:17:34 +00:00Commented Jan 27, 2011 at 10:17
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4 Answers
>>> import socket
>>> def get_ips_for_host(host):
try:
ips = socket.gethostbyname_ex(host)
except socket.gaierror:
ips=[]
return ips
>>> ips = get_ips_for_host('www.google.com')
>>> print(repr(ips))
('www.l.google.com', [], ['74.125.77.104', '74.125.77.147', '74.125.77.99'])
Comments
Python 3.1.3 (r313:86834, Nov 27 2010, 18:30:53) [MSC v.1500 32 bit (Intel)] on win32
>>> import socket
>>> socket.gethostbyname('cool-rr.com')
'174.120.139.162'
Note that:
- gethostbyname() doesn't work with IPv6.
- gethostbyname() uses the C call gethostbanme(), which is deprecated.
If these are problematic, use socket.getaddrinfo() instead.
Comments
The easiest way is to use socket.gethostbyname(). This does not support IPv6, though, and is based on the deprecated C call gethostbanme(). If you care about these problems, you can use the more versatile socket.getaddrinfo() instead.
Comments
Here is full example, how you can get a website's IP address using Python
import urllib.parse
import socket
import dns.resolver
def get_ip(target):
try:
print(socket.gethostbyname(target))
except socket.gaierror:
res = head(target, allow_redirects=True)
try:
print(r.headers['Host'])
except KeyError:
parsed_url = urllib.parse.urlparse(target)
hostname = parsed_url.hostname
try:
answers = dns.resolver.query(hostname, 'A')
for rdata in answers:
print(rdata.address)
except dns.resolver.NXDOMAIN:
print('ip not found')
get_ip('example.com')
