I am trying to parse JSON, but it gives the wrong result.
var obj = JSON.parse('[{ "name":"John", "age":30, "city":"New York"}]');
alert(obj);Please check the code and provide me any suggestion.
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1you cannot alert object use console.log(obj);Deepak Kumar T P– Deepak Kumar T P2017-12-28 10:18:28 +00:00Commented Dec 28, 2017 at 10:18
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1There is nothing wrong, you are parsing an array. Open the console of your browser and try: var obj = JSON.parse('[{ "name":"John", "age":30, "city":"New York"}]'); obj[0]; // this will print an object.brduca– brduca2017-12-28 10:23:49 +00:00Commented Dec 28, 2017 at 10:23
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"it gives the wrong result" — It gives the result I'd expect it to give. What result do you expect it to give?Quentin– Quentin2017-12-28 10:39:04 +00:00Commented Dec 28, 2017 at 10:39
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3 Answers
You can not alert() objects. So Use console.log() instead of alert().
By The Way you can alert() individual values.
Working snippet:-
var obj = JSON.parse('[{ "name":"John", "age":30, "city":"New York"}]');
console.log(obj);
alert(obj[0].name); // you can alert values
alert(obj[0].age); // you can alert values
alert(obj[0].city); // you can alert values
answered Dec 28, 2017 at 10:19
Death-is-the-real-truth
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2 Comments
Ashish Rana
Thanks for this valuable answer, I have one more question, can i ask?
Death-is-the-real-truth
@AshishRana yes you can ask.
You can also use eval() to parse json string
var test = '[{ "name":"John", "age":30, "city":"New York"}]';
var obj = eval ("(" + test + ")");
console.log(obj);
//console.log(obj[0].name);Comments
You have an array in json object you can get the json object
values by referencing the key name.
alert(obj[0].name);
alert the value of json object at 0 index and by providing the key name.
<script>
var obj = JSON.parse('[{ "name":"John", "age":30, "city":"New York"}]');
alert(obj);
alert(obj[0].name);
</script>
