[('1950', '6.5', '6.4', '6.3', '5.8', '5.5', '5.4', '5.0', '4.5', '4.4', '4.2',
'4.2', '4.3', ' \n')]
How can I sum up the values from position [1] to [12]?
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note that the solutions mention your_list[0] to reference the tuple that is the first elements of your list (I'm not sure if this was intended or not)Peter Gibson– Peter Gibson2011-01-25 00:59:21 +00:00Commented Jan 25, 2011 at 0:59
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4 Answers
Convert to float and sum using a list comprehension:
sum(float(x) for x in my_list[0][1:13])
edit: eeks, range was wrong. edited per comments.
1 Comment
John La Rooy
careful, this one only sums from position 1 to 11!
L=[('1950', '6.5', '6.4', '6.3', '5.8', '5.5', '5.4', '5.0', '4.5', '4.4', '4.2', '4.2', '4.3', ' \n')]
sum(map(float,L[0][1:13]))
Comments
If you want to avoid creating an extra temporary list, you can use islice
>>> from itertools import islice
>>> L=[('1950', '6.5', '6.4', '6.3', '5.8', '5.5', '5.4', '5.0', '4.5', '4.4', '4.2', '4.2', '4.3', ' \n')]
>>> sum(map(float,islice(L[0],1,13)))
62.5
Comments
You could use a lambda and reduce.
lst = [('1950', '6.5', '6.4', '6.3', '5.8', '5.5', '5.4', '5.0', '4.5', '4.4', '4.2', '4.2', '4.3', ' \n')]
lst_sum = reduce(lambda x, y : float(x) + float(y), lst[0][1:12])
1 Comment
John La Rooy
don't use
sum as a variable name as it clashes with the builtin function sum - which coincidentally does the same job as the reduce+lambda. I think the OP expects the items to be added as floats, not as strings