Git for windows bash execution path for a script not correct

Question

When the code

SRC=$(cd $(dirname "$0"); pwd)

is executed inside a Bash script on a system that has Git for Windows installed in c:\program files\Git, the SRC will get the value /c/program.

How do I make this work? I need to get the path to where the script is and use that to include other scripts with a relative path. In my case the next line is: source "${SRC}/common/common.sh"

The script is in c:\program files\Git\usr\bin so I can use git <command-name> and extend Git with some useful hand-made commands for feature branch workflow with rebase and submodules.
The source code is at https://github.com/jlovs/git-scripts if anyone want to help out.

Please share more information about the environment: Are you running under Cygwin? — Yaniv Shaked
– Yaniv Shaked, Commented Dec 13, 2017 at 7:34
@JanLovstrand – there may be some ambiguity in exactly what you are asking. After reading it a second time, I honestly have no clue. What do you want SRC to be exactly? — Travis Clarke
– Travis Clarke, Commented Dec 13, 2017 at 8:49
Wait, I think I get it. You need to resolve the src directory: how about SRC=$( cd "$( dirname "${BASH_SOURCE[0]}" )" && pwd ) — Travis Clarke
– Travis Clarke, Commented Dec 13, 2017 at 8:54
@JanLovstrand – if this is incorrect please clarify the question. — Travis Clarke
– Travis Clarke, Commented Dec 13, 2017 at 8:56

Melebius · Accepted Answer · 2017-12-13 13:11:25Z

4

You need to double-quote the argument of the cd command.

SRC=$(cd "$(dirname "$0")"; pwd)

The command substitution $(dirname "$0") expands to a path containing a space. The following cd command gets two arguments while you want to pass just one, with a space inside.

You don’t need to worry about the quotes around $0 inside another pair of quotes since the $() command substitution starts a new quoting context.

edited Dec 13, 2017 at 13:11

answered Dec 13, 2017 at 8:00

Melebius

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4 Comments

Travis Clarke Over a year ago

This answer is perfectly valid, but for the double quote lovers out there (which I assume all Windows users need to be): SRC="$(cd "$(dirname "$0")"; "pwd")"

Jan Lovstrand Over a year ago

This one works. Sorry if I didn't notice that it was an included script that had the same error. Thank you all!

phd Over a year ago

Shouldn't you escape internal quotes? SRC=$(cd "$(dirname \"$0\")"; pwd)

Melebius Over a year ago

@phd No, see the last paragraph of my updated answer.

Yaniv Shaked · Accepted Answer · 2017-12-13 09:00:14Z

0

As you stated, you are running under MINGW64. You can try to use cygpath -aw to convert the path to windows format:

SRC=$(cygpath -aw $(cd "$(dirname "$0")"; pwd))

More information here and here.

answered Dec 13, 2017 at 9:00

Yaniv Shaked

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3 Comments

Jan Lovstrand Over a year ago

Think the problem is in the $(dirname "$0") part of the line, because this gives me a "too many arguments" error. I think that the space in the path has to be escaped like /c/Program\ Files/Git/usr/bin, but don't know how to make that happen. Tried cygpath -u, but it gives me /c/Program Files/usr/bin

Yaniv Shaked Over a year ago

Try cygpath -aw

Yaniv Shaked Over a year ago

Please verify spaces, quotes, etc

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