Python's exec running in module works but in function not

Question

This works:

import os
import sys
with open('tests.py') as fptr:
    script_content = fptr.read()
exec(script_content)

And this not:

def run():
    import os
    import sys
    with open('tests.py') as fptr:
        script_content = fptr.read()
    exec(script_content)

run()

Result:

Traceback (most recent call last):
  File "tmp.py", line 8, in <module>
    run()
  File "tmp.py", line 6, in run
    exec(script_content)
  File "<string>", line 15, in <module>
  File "<string>", line 16, in PlaceSpitter
NameError: name 'Place' is not defined

Could anyone tell my why and how to fix it?

xliiv · Accepted Answer · 2017-12-01 11:15:59Z

1

I've read again - carrefully - python's docs especially this one:

Remember that at module level, globals and locals are the same dictionary

And try this:

def run():
    import os
    import sys
    with open('tests.py') as fptr:
        script_content = fptr.read()
    exec(script_content, globals())

run()

which now works!

I still don't know why but now at least it works.

answered Dec 1, 2017 at 11:15

xliiv

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