Identify the strings in python array [duplicate]

Question

I have a data similar to,

import numpy as np
A = np.array( [['1','2','3'], ['a','3','5']] )

Now I want to identify the cell address of 'a'. I have tried the following code for that purpose,

for i in range(0,2):
    for j in range(0,3):
        if (type(float(A[i,j])) == float):
            print(str(i)+str(j))

since, 'a' can't be converted into floating point it shows the following error.

00

01

02

Traceback (most recent call last):

File "", line 3, in

if (type(float(A[i,j])) == float):

ValueError: could not convert string to float: 'a'

Please help. Thank you in advance.

Don't you need to use A[i][j] or is that some fancy numpy magic? — Sumner Evans
– Sumner Evans, Commented Nov 20, 2017 at 18:41
Your data is going to be just one character? Then you could use isdigit and so docs.python.org/3/library/stdtypes.html — fernand0
– fernand0, Commented Nov 20, 2017 at 18:41
@SumnerEvans the __getitem__ of numpy arrays accepts tuples! — timgeb
– timgeb, Commented Nov 20, 2017 at 18:45
everything is a string in your array. Why are you even using numpy here? — juanpa.arrivillaga
– juanpa.arrivillaga, Commented Nov 20, 2017 at 18:45
@timgeb, that's cool! I've never used numpy before, so that's really neat. — Sumner Evans
– Sumner Evans, Commented Nov 20, 2017 at 18:46

saurabh deokate · Accepted Answer · 2017-11-20 18:50:08Z

1

You can try this

import numpy as np

def is_number(s):
   try:
    int(s)
    return True
   except ValueError:
    return False

A = np.array( [['1','2','3'], ['a','3','5']] )

for i in range(0,2):
    for j in range(0,3):
        if not is_number(A[i][j]):
            print i , j

answered Nov 20, 2017 at 18:50

saurabh deokate

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