parsing json with jquery

Question

$(document).ready(function()
{

$.ajax({
method: "get",
url: 'ctr_seearmylist.php',
dataType: 'json',
data: 'get="squad"',
success: processSquads()
});

});

function processSquads(response)
{
alert(response);

}

Why isn't it working? How can I use the Json result that I'm getting? The Json result looks like this[[1,2]][[1,2]]

This is how the php function that is called looks like: {...... $temp[0]=$id; $temp[1]=$squad_id;

$result[]=$temp;
}
$result=json_encode($result);
return $result;

I looked at the response I get in firebug and I receive this: [["1","12"],["2","3"],["3","7"]] but I can't manage to write it out. I would want to write out just 1, 2, 3, but I can't even write it as it is.

I should mention that I tried to parse it using jQuery.parseJSON, but in the function process squad doesn't even get send the parameter. what am I doing wrong?

@shybovycha; it is declared before it's used, the call is when body has loaded (call back), the function is declared immediately. — falstro
– falstro, Commented Jan 16, 2011 at 19:36
@shybovycha: Declaring a function with the "function identifier(...){}"-syntax actually declares it in the beginning of its scope, so even if it wasn't used as a callback as roe pointed out, it would still work. Read about "hoisting" if you're curious. — Jakob
– Jakob, Commented Jan 16, 2011 at 20:18

polarblau · Accepted Answer · 2011-01-16 19:35:30Z

2

Leave the parenthesis way from the callback definition:

$.ajax({
    method: "get",
    url: 'ctr_seearmylist.php',
    dataType: 'json',
    data: 'get="squad"',
    success: processSquads
});

If you want control over what is exactly passed into your callback method, you can wrap the definition into an anonymous function — e.g.:

$.ajax({
    method: "get",
    url: 'ctr_seearmylist.php',
    dataType: 'json',
    data: 'get="squad"',
    success: function(data, textStatus, XMLHttpRequest) {
         processSquads(data, XMLHttpRequest);
    }
});

answered Jan 16, 2011 at 19:35

polarblau

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Comments

falstro · Accepted Answer · 2011-01-16 19:34:51Z

0

success: processSquads()

This line actually calls 'processSquads', I think you want jQuery to call it when it's done...

success: processSquads

HTH.

answered Jan 16, 2011 at 19:34

falstro

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1 Comment

Pillblast Over a year ago

Thank you, now the function can see the parameter, but I still have a problem selecting only some things from it. I tried iterating through it in a for and addressing it by response.items[i] but it's not working

Dennis Kreminsky · Accepted Answer · 2011-01-16 19:36:21Z

0

jQuery documentation states that:

success(data, textStatus, XMLHttpRequest)

A function to be called if the request succeeds. The function gets passed three arguments: The data returned from the server, formatted according to the 'dataType' parameter; a string describing the status; and the XMLHttpRequest object (available as of jQuery 1.4). This is an Ajax Event.

So, you have to make sure arguments are right.

answered Jan 16, 2011 at 19:36

Dennis Kreminsky

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