Python - How to pass a variable from one method to another in Python?

Question

I've looked around for a question like this. I've seen similar questions, but nothing that really helped me out. I'm trying to pass the choice variable from the method rollDice() to the method main(). This is what I've got so far:

import random
import os
import sys

def startGame():
     answer = input('Do you want to play Super Dice Roll?\nEnter 1 for Yes\nEnter 2 for No\n'
     os.system('cls')
     if (answer == '1'):
          rollDice()
     elif(answer == '2'):
          print('Thank you for playing!')
     else:
          print('That isn/t a valid selection.')
          StartGame()

def rollDice():
     start = input('Press Enter to roll dice.')
     os.system('cls')
     dice = sum(random.randint(1,6) for x in range (2))
     print('you rolled ',dice,'\n')
     choice = input('Do you want to play again?\nEnter 1 for Yes\nEnter 2 for No.\n)
     return choice

def main():
     startGame()
     while (choice == '1'):
          startGame()
     print('Thank you for playing')

print('!~!~!~!~WELCOME TO SUPER DICE ROLL~!~!~!~!~\n')
main()

I know that I may have other things in here that are redundant or I may have to fix, but I'm just working on this one issue right now. I'm not sure how to pass the choice variable into the main() method. I've tried putting choice == rollDice() in the main() method but that didn't work. I do mostly SQL work, but wanted to start learning Python and I found a website that has 5 beginner tasks but virtually no instructions. This is task one.

I'd recommend another site if this is task 1 and there is no instruction — depperm
– depperm, Commented Oct 19, 2017 at 15:31
@depperm, yes you're right. The code is on another machine and I was just typing it out and missed that part. However, I do have that included. Yeah, I understand trying another site. I just felt like the more research I had to do the more I'd learn. — AP1
– AP1, Commented Oct 19, 2017 at 15:42

mrCarnivore · Accepted Answer · 2017-10-19 16:13:52Z

1

You need to put the return value of the function into a variable to be able to evaluate it (I also corrected a few bugs in your code, mainly typos):

import random
import os

def startGame():
    answer = input('Do you want to play Super Dice Roll?\nEnter 1 for Yes\nEnter 2 for No\n')
    os.system('cls')
    while answer == '1':
        answer = rollDice()
    if answer == '2':
        print('Thank you for playing!')
    else:
        print('That isn/t a valid selection.')
        startGame()

def rollDice():
    input('Press Enter to roll dice.')
    os.system('cls')
    dice = sum(random.randint(1,6) for x in range (2))
    print('you rolled ', dice, '\n')
    choice = input('Do you want to play again?\nEnter 1 for Yes\nEnter 2 for No.\n')
    return choice

def main():
    print('!~!~!~!~WELCOME TO SUPER DICE ROLL~!~!~!~!~\n')
    startGame()
    print('Thank you for playing')


main()

edited Oct 19, 2017 at 16:13

answered Oct 19, 2017 at 15:32

mrCarnivore

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5 Comments

AP1 Over a year ago

Thank you for your answer. This leads me to another question: If I declare that choice = '1' in the main() then won't it always end up as '1' no matter what the user inputs? What if the user chooses not to play again and selects '2'?

mrCarnivore Over a year ago

The choice='1' is just the default value to get the game started for the first time. in choice = startGame() the variable is overwritten with the actual user input which is then used for the next time the while loop is run.

mrCarnivore Over a year ago

I you do like my answer I would appreciate if you could accept it (the check mark below the vote button). Thank you.

AP1 Over a year ago

Ok. I tried that out and I had to debug. When I ran it step by step it followed fine until I chose '2' as the user input. It chose the correct path of the IF statement and then when it printed 'Thank you for playing!' and it stored '2' for choice. But then it went back to the while loop and checked the value of choice and determined that choice was equal '1'. I'm not sure if it passed the input value to the main. I'm thinking that maybe because it didn't pass the value '2' that when it went back to the main it kept that instance of choice that it already knew at '1'?

mrCarnivore Over a year ago

@AP1: I have updated my answer. Now it works as you would expect it to. The structure before was too complicated for this task. So I simplified it even more.

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