2

I have found the following Python code from Stackoverflow which opens a file called sort.txt, and then sorts the the numbers contained in the file.

The code works perfect. I was wondering how I could then save the sorted data to another text file. Every time I try, the saved file is shown empty. Any help would be appreciated. I would like the saved file to be called sorted.txt

with open('sort.txt', 'r') as f:
    lines = f.readlines()
numbers = [int(e.strip()) for e in lines]
numbers.sort()
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3 Answers 3

Reset to default
1

You can use this with f.write() :

with open('sort.txt', 'r') as f:
    lines = f.readlines()

numbers = [int(e.strip()) for e in lines]
numbers.sort()

with open('sorted.txt', 'w') as f: # open sorted.txt for writing 'w'
    # join numbers with newline '\n' then write them on 'sorted.txt'
    f.write('\n'.join(str(n) for n in numbers))

Input (sort.txt):

1
-5
46
11
133
-54
8
0
13
10

Output (sorted.txt):

-54
-5
0
1
8
10
11
13
46
133
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Comments

1

With <file object>.writelines() method:

with open('sort.txt', 'r') as f, open('output.txt', 'w') as out:
    lines = f.readlines()
    numbers = sorted(int(n) for n in lines)
    out.writelines(map(lambda n: str(n)+'\n', numbers))
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Comments

0

Get sorted data from the current file and save to a variable. Open the new file in write mode ('w')and write the data from saved variable to the file.

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