This is an array:
total = ["10%", 1000, "5%", 2000]
How can I filter these into two arrays like:
percentage = ["10%","5%"]
absolute = [1000,2000]
...using JavaScript array filter.
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Are the values will be in this order only ["percentage', 'absolute', ...] ?abhishekkannojia– abhishekkannojia2017-08-28 09:50:10 +00:00Commented Aug 28, 2017 at 9:50
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1You really did not search? SO has many Q&A on such filters.trincot– trincot2017-08-28 09:51:01 +00:00Commented Aug 28, 2017 at 9:51
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9 Answers
You should use filter method, which accepts a callback function.
The filter() method creates a new array with all elements that pass the test implemented by the provided function.
Also, use typeof operator in order to find out the type of item from array. The typeof operator returns a string indicating the type of the unevaluated operand.
let total = ["10%", "1000", "5%", "2000"];
let percentage = total.filter(function(item){
return typeof item == 'string' && item.includes('%');
});
console.log(percentage);
let absolute = total.filter(function(item){
return typeof item == 'number' || !isNaN(item);
});
console.log(absolute);
answered Aug 28, 2017 at 9:50
Mihai Alexandru-Ionut
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Comments
let total = ["10%", 1000, "5%", 2000];
let percents = total.filter(item => item.toString().includes('%'));
let numbers = total.filter(item => !item.toString().includes('%'));
console.log(percents, numbers);
Make two arrays from one array by separating number and string using advance
js.
let total = ["10%", 1000, "5%", 2000];
var percentage = total.filter(e => isNaN(e));
var absolute = total.filter(e => !isNaN(e));
console.log({percentage , absolute});
Comments
You can use regular expressions since you have only strings in your array.
For % :
total.filter(function(element){
return /^[0-9]+\%$/gi.test(element);
});
For absolute :
total.filter(function(element){
return /^[0-9]+$/gi.test(element);
});
Comments
You can use Array#reduce to split the array:
const total = ["10%", 1000, "5%", 2000];
const { absolute, percentage } = total.reduce((arrs, item) => {
const key = typeof item === 'number' ? 'absolute' : 'percentage';
arrs[key].push(item);
return arrs;
}, { percentage: [], absolute: [] });
console.log(absolute);
console.log(percentage);
Comments
For brevity with using ES2015 , if you plan to simply clear the array (this is an example, insert your own function for element "e", of course):
let MyArray = [1,2,3,4,5]
MyArray = [].concat(MyArray.filter(e => e > 2))
console.log(MyArray)
Comments
you can do it using
let total = ["10%", 1000, "5%", 2000]
let result1 = total.filter(function(element){
if(typeof element == "number"){
return 1;
}
return 0;
})
let result2 = total.filter(function(element){
if(typeof element == "string" && element.match(/\%$/)){
return 1;
}
return 0;
})
console.log(result1, result2);the first array filter all the number
the 2nd array filter elements which are a string and have a "%" in the end
Comments
use this code
$array = array('10%', '1000', '20%','2000');
//for show integer from array
print_r(array_filter($array, function ($var) { return (stripos($var, '%') === false); }));
//for show % array
print_r(array_filter($array, function ($var) { return (stripos($var, '%') == true); }));
Comments
let total = ["10%", "1000", "5%", "2000"];
let percentage = total.filter(function(item){
return typeof item == 'string' && item.includes('%');
});
console.log(percentage);
let absolute = total.filter(function(item){
return typeof item == 'number' || !isNaN(item);
});
console.log(absolute);
