Javascript: Regex removes the spaces?

Question

I have this code that removes any Numeric values from an input field.

This works fine but the issue is that it will also remove the Spaces too which is not wanted.

This is my code:

$(document).on('keyup','.myclassname', function(e){
  var regexp = /[^a-zA-Z]/g;
  if($(this).val().match(regexp)){
    $(this).val( $(this).val().replace(regexp,'') );
  }
});

Can someone please advice on this?

/[^a-zA-Z]/g is any character that's no in the alphabet, including whitespace and punctuation (and numbers, which you want). — jdubjdub
– jdubjdub, Commented Aug 17, 2017 at 16:35
See this stackoverflow.com/questions/45730059/… for the same issue. — OwChallie
– OwChallie, Commented Aug 17, 2017 at 16:36
You can examine what keycode user attempted to enter and forbid entry if it is numeric instead of replacing it after entry. — Killer Death
– Killer Death, Commented Aug 17, 2017 at 16:37
Possible duplicate of Removing Numbers from a String using Javascript — Mouser
– Mouser, Commented Aug 17, 2017 at 16:39

Dij · Accepted Answer · 2017-08-17 16:37:34Z

3

your regex currently matches everything that is not english alphabet, if you only want to remove numeric content you can /[0-9]/g or /\d/g

  var str = "1A3 AAA";
  var regexp = /[0-9]/g;
  console.log(str.replace(regexp, ""));

edited Aug 17, 2017 at 16:37

answered Aug 17, 2017 at 16:35

Dij

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2 Comments

Mouser Over a year ago

You can improve this by using \d. Which is shorthand for [0-9]

jdubjdub Over a year ago

str.replace(/\d/g, '') would work too, to use the \d wildcard

Rudy Palacios · Accepted Answer · 2017-08-17 16:47:55Z

A quick answer would be to change this

var regexp = /[^a-zA-Z]g;

To this

[^a-zA-Z\s]

This means: Match a single character not present in the list below, characters from a-z, A-Z and \s (any whitespace character)

A shorter version, would be:

[0-9]+

This means: Match a single character PRESENT in the list below, Matching between one and unlimited times, only numbers from 0 to 9, achieving what you are really trying to do "remove any numeric values"

An even shorter version, would be:

[\d]+

Wich is equal to [0-9]+

Previously, you are excluding the characters you don't want, but is easier, shorter and faster if you select only the ones you want.

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