PHP check if array key exist

Question

I have a array and within that array i have more elements. I want to check if a specific element exist

  $jsondata = file_get_contents('php://input');
  $jsonobj = json_decode($jsondata, true);

Possibility 1

$jsonobj=Array(
      [user] => Array
            (
              [userId] => 1501148600220
              [locale] => en-US
                // no TOKEN
            )
);

Possibility 2

$jsonobj=Array(
          [user] => Array
                (
                  [userId] => 1501148600220
                  [locale] => en-US
                  [token] => 12345    // TOKEN exist
                )
               );

The follwing is a decoded JSON.
The Received JSON sometimes might and might not contain the element 'token'.

I want to check if the $jsonobj has the element 'token'

    if (array_key_exists('token', $jsonobj)) {
    echo "Element is in the array";
    }

How do i check this according to the structure of my array?

UPDATE

Sometimes, the jsonobj might not contain anything. It could be empty. If it is empty i get an error

PHP Warning:  array_key_exists() expects parameter 2 to be array

Well, you obviously decode the JSON string to have an object or array and then check if that element or property exists. What is the question here? — arkascha
– arkascha, Commented Jul 27, 2017 at 10:20

Bibhudatta Sahoo · Accepted Answer · 2017-07-27 10:38:46Z

3

You just need to pass the index 'user' in the multidimensional $jsonobj array

Like this

if (array_key_exists('token', $jsonobj['user'])) {
  echo "Element is in the array";
 }

Modified:-

$jsonobj=json_decode($jsonobj,true);
if(!empty($jsonobj['user'])&&is_array($jsonobj['user']))
{
    if (array_key_exists('token', $jsonobj['user'])) {
        echo "Element is in the array";
    }
}

edited Jul 27, 2017 at 10:38

answered Jul 27, 2017 at 10:24

Bibhudatta Sahoo

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2 Comments

Elo97234c Over a year ago

I get an error, PHP Warning: array_key_exists() expects parameter 2 to be array

Bibhudatta Sahoo Over a year ago

Try the modified answer

astrocrack · Accepted Answer · 2017-07-27 10:22:16Z

3

 if (array_key_exists('token', $jsonobj['user'])) {
  echo "Element is in the array";
 }

answered Jul 27, 2017 at 10:22

astrocrack

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2 Comments

Elo97234c Over a year ago

I get an error, PHP Warning: array_key_exists() expects parameter 2 to be array

astrocrack Over a year ago

Yes. It was the empty array case. Just saw that someone sorted that out. Nice

Virb · Accepted Answer · 2017-07-27 10:25:13Z

1

You have to check your $jsonobj array key that is user. So, if you want to check user array key then you should write like this,

if (array_key_exists('token', $jsonobj['user'])) 
{
  echo "Element is in the array";
}

See this Manual.

answered Jul 27, 2017 at 10:25

Virb

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Comments

Prince · Accepted Answer · 2017-07-27 10:52:41Z

1

foreach($jsonobj as $obj => $val){
    if(is_array($val)){     
        if(array_key_exists('token', $val)){
            echo 'exist';
        }else{
            echo 'not exist';
        }
    }
}

answered Jul 27, 2017 at 10:52

Prince

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Comments

Minwork · Accepted Answer · 2020-01-24 16:39:11Z

0

You can always use this one liner to check if nested key exists in array:

Arr::has($jsonobj, 'user.token');
// Or
Arr::has($jsonobj, ['user', 'token']);

If you want to learn more about this method or other methods useful when dealing with multidimensional arrays check out this php array library

answered Jan 24, 2020 at 16:39

Minwork

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