Sort an array by string value

Question

How can I sort an array by string value?

If I have an array such as ['you', 'I', 'me', 'me', 'will', 'me'], how can I get all the indexes with the word me at the front of the array?

I have tried using array.sort, but it does not seem to be working.

e.target.value is the an value I am getting from a <select element in the dom.

arr.sort((a, b) => {
    if (a < e.target.value) {
        return -1;
    }
    if (a > e.target.value) {
        return 1;
    }

    return 0;
});

UPDATE: Yury's answer works very well, but what if I need to match two values in an array of objects and have those sorted.

Example:

arr = [
  {id: 1, name: "cookie"}, 
  {id: 2, name: 'foo'}, 
  {id: 3, name: 'bar'}, 
  {id: 2, name: 'foo'}
];

How can I place all the elements with the id '2' and with the name 'foo' at the front of the array?

yes, and then move all of those indexes with the word "me" to the front of the array. So index 0, 1, and 2 should be me and then index 3, 4, 5 should be 'you', 'I', and 'will' — henhen
– henhen, Commented Jun 27, 2017 at 21:29
Shouldn't it be ['me','me','me','I','you','will'] if you want them sorted? — Heretic Monkey
– Heretic Monkey, Commented Jun 27, 2017 at 21:36
the rest of the values dont matter, I just want the key word 'me' to be at the front of the array — henhen
– henhen, Commented Jun 27, 2017 at 21:39

Yury Tarabanko · Accepted Answer · 2017-06-27 21:46:44Z

4

You could use sort

let a = ['you', 'I', 'me', 'me', 'will', 'me'];

a.sort((a, b) => a !== b && b === 'me' ? 1 : 0);

console.log(a)

edited Jun 27, 2017 at 21:46

answered Jun 27, 2017 at 21:35

Yury Tarabanko

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3 Comments

Christos Over a year ago

Very nice approach (+1) from me.

henhen Over a year ago

what if you want have two match by two values in an object? I have updated my question to include this problem.

Yury Tarabanko Over a year ago

Use b.propname to access property you want to compare

elqueso101 · Accepted Answer · 2017-06-28 00:22:45Z

const arr = [
  {id: 1, name: "cookie"},
  {id: 2, name: 'foo'},
  {id: 3, name: 'bar'},
  {id: 2, name: 'foo'}
];

Use the Array.prototype.sort() method on arr using a callback function that switches the order of items only if the first one does not match the given criteria and the second one does.

arr.sort((item1, item2) => {
  if((item1.id !== 2 || item1.name !== 'foo') && (item2.id === 2 || item2.name === 'foo')) {
    return 1;
  }

  return 0;
});

console.log(arr);

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