I am trying to do the following :
#!/bin/bash
echo "Enter Receiver HostNames (comma separated hostname list of receivers):"
read receiverIpList
receiver1=`$receiverIpList|awk -F, '{print $1}'`
echo $receiver1
when I run the script I am getting below error.
./test1.sh
Enter Receiver IP Addresses (comma separated IP list of receivers):
linux1,linux2
./test1.sh: line 6: linux1,linux2: command not found
Could someone please tell me what's wrong in the script??
The syntax you're trying to use would be:
receiver1=`echo "$receiverIpList"|awk -F, '{print $1}'`
but your approach is wrong. Just read the input directly into a bash array and use that:
$ cat tst.sh
echo "Enter Receiver HostNames (comma separated hostname list of receivers):"
IFS=, read -r -a receiverIpList
for i in "${!receiverIpList[@]}"; do
printf '%s\t%s\n' "$i" "${receiverIpList[$i]}"
done
$ ./tst.sh
Enter Receiver HostNames (comma separated hostname list of receivers):
linux1,linux2
0 linux1
1 linux2
Even if you didn't want to do that for some reason, you still shouldn't use awk, just use bash substitution or similar, e.g.:
$ foo='linux1,linux2'; bar="${foo%%,*}"; echo "$bar"
linux1
Be careful of your spelling btw as in your posted code sample you're sometimes spelling receiver correctly (receiver) and sometimes incorrectly (reciever) - that will probably bite you at some point when you're trying to use a variable name but actually using a different one instead due to flipping the ei. The question has now been fixed to avoid this problem, I see.
