bash read does not wait for input

Question

I have this code:

#!/bin/bash
for some_host in $(cat some_list); do
    echo $some_host
    ssh $some_host sudo cat /etc/some.conf |grep -i something_to_grep
    printf "\nPut the input: " read some_input
    echo $some_input
    
done

When I run it, it just continues without waiting for my input. I need to copy/past something form ssh output for further action :/

change to echo "Put the input: " ; read some_input

P....
– P....

2017-06-01 09:52:14 +00:00
Commented Jun 1, 2017 at 9:52 — P....
– P...., Commented Jun 1, 2017 at 9:52
You aren't running read at all.

chepner
– chepner

2017-06-01 13:02:05 +00:00
Commented Jun 1, 2017 at 13:02 — chepner
– chepner, Commented Jun 1, 2017 at 13:02

Shammel Lee · Accepted Answer · 2017-06-02 07:38:02Z

3

Change

printf "\nPut the input: " read some_input

to

read -p "Put the input: " some_input

Example

for host in '1.1.1.100' '1.1.1.101' '1.1.1.102'
do
    read -p "Enter your input for ${host} " host_input
    echo "${host} says ${host_input}"
done

edited Jun 2, 2017 at 7:38

answered Jun 2, 2017 at 7:31

Shammel Lee

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