How to execute a linux shell script from a C# application?

Question

I have a linux shell script which I can execute manually with CygWin terminal in windows.

sh E://Work/sync.sh E://Work/Voice/Temp

But I'm having some difficulty when I'm trying to run the shell script in my C# application with the same argument.

string command = "E://Work/sync.sh E://Work/Voice/Temp";
ProcessStartInfo psi = new ProcessStartInfo(@"C:\cygwin64\bin\bash.exe", command);
psi.RedirectStandardError = true;
psi.RedirectStandardOutput = true;
psi.UseShellExecute = false;
Process p = Process.Start(psi);
Console.WriteLine(p.StandardError.ReadToEnd());
Console.WriteLine(p.StandardOutput.ReadToEnd());

It's giving me error:

E://Work/sync.sh: line 47: rm: command not found
E://Work/sync.sh: line 48: mkdir: command not found
E://Work/sync.sh: line 50: ls: command not found
E://Work/sync.sh: line 59: ls: command not found
E://Work/sync.sh: line 60: rmdir: command not found

Then I tried a different approach.

ProcessStartInfo psi = new ProcessStartInfo(@"C:\cygwin64\bin\bash.exe");
psi.Arguments = "--login -c sh E://Work/sync.sh  E://Work/Voice/Temp";
Process p = Process.Start(psi);

This initiates a CygWin command prompt like this:

Then if I enter my command manually it works. E://Work/sync.sh E://Work/Voice/Temp

How can I execute the script automatically from my application without any manual input?

try psi.Arguments = "--login -c /cygdrive/e/Work/sync.sh /cydrive/e/Work/Voice/Temp"; — matzeri
– matzeri, Commented May 25, 2017 at 16:35

Ali Akber · Accepted Answer · 2020-02-10 23:42:10Z

1

After doing some google search, I found a way to do this. All I had to do is change "--login -c" to "--login -i"

ProcessStartInfo psi = new ProcessStartInfo(@"C:\cygwin64\bin\bash.exe");
psi.Arguments = "--login -i E://Work/sync.sh  E://Work/Voice/Temp";
Process p = Process.Start(psi);

edited Feb 10, 2020 at 23:42

answered May 29, 2017 at 9:19

Ali Akber

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