Print exception details recursively while using try except [duplicate]

Question

#!/usr/bin/env python

#import re


def test_ex1(input):
    if re.match(r'^[A-Z]+$',input):
        print 'Match'
        return True
    print 'No Match'
    return False   


#test_ex1('ABC')
try:
    test_ex1('ABC')
except Exception:
    raise Exception

If I run the above program,it will print following exception message.

a:~/Python> python test.py
Traceback (most recent call last):
  File "test.py", line 18, in <module>
    raise Exception
Exception

What is the right way in Python to make it print the following stack trace while catching exception using try except without changing test_ex1 subroutine?

Traceback (most recent call last):
  File "test.py", line 15, in <module>
    test_ex1('ABC')
  File "test.py", line 8, in test_ex1
    if re.match(r'^[A-Z]+$',input):
NameError: global name 're' is not defined

Answer 1

One way is using the traceback module

import traceback

try:
  re.match()
except Exception:
  traceback.print_exc()

Answer 2

I once used following to print all traceback as:

import sys

try:
    # code here
except Exception:
    print(sys.exc_info()[0])

The raise keyword is being used to throw your error up to the stack and handle at upper level of function call.