How to find differencing value between two arrays and return value from third array?

Question

I would like to compare two arrays and use the differencing value to return another value from another array.

With this snippet I am able to determe that "b" from $array1 is not contained in $array2. However, I don`t know how to link "b" to 2 in $array3 and return that value.

$array1 = (@("a","b","c"))
$array2 = (@("a","c"))
$array3 = (@(1,2,3))  # 1 should be linked to "a", 2 to "b" and 3 to "c"

$array1 | ForEach-Object {If ($_ -notin $array2) {$_}}

I appreciate your help.

Thanks.

Ramana · Accepted Answer · 2017-05-10 12:29:20Z

1

You can use compare-object

$array1 = @("a","b","c")
$array2 = @("a","c")
$array3 = @(1,2,3)  # 1 should be linked to "a", 2 to "b" and 3 to "c"

$diff = Compare-Object -ReferenceObject $array1 -DifferenceObject $array2  -PassThru

$diff | ForEach-Object { if($array1.Contains($_)){
       write-host $array3[$array1.IndexOf($_)]
   }
}

answered May 10, 2017 at 12:29

Ramana

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Comments

Ansgar Wiechers · Accepted Answer · 2017-05-10 12:35:15Z

1

Something like this should work:

$index = 0..($array1.Count-1) | Where-Object { $array1[$_] -notin $array2 }
if ($index) { $array3[$index] }

edited May 10, 2017 at 12:35

answered May 10, 2017 at 12:10

Ansgar Wiechers

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2 Comments

Kirill Pashkov Over a year ago

There is a typo in your code. Replace $array1[$i] to $array1[$_]

Ansgar Wiechers Over a year ago

Indeed. Thanks for the heads up. Fixed.

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