Batch script error "The syntax of the command is incorrect"

Question

I have a batch file that is throwing a syntax error at a particular line.

@ECHO ON
CD %~dp0
SET XDA_HOME_DIR=%CD:~0,-4%
SET "JAVAHOME=%JAVA_HOME%"
SET XDA_CONFIG_PROPERTIES=%XDA_HOME_DIR%\config\xda-config.properties
IF "%JAVAHOME%"== ""( 
ECHO JAVA_HOME not set
GOTO END)

Note: This is not the full script. I have posted just a part of it.

Below is the error thrown:

What is causing the syntax error message?

npocmaka · Accepted Answer · 2017-05-09 09:55:19Z

2

error comes from here:

IF "%JAVAHOME%"== ""( 
ECHO JAVA_HOME not set
GOTO END)

you need a space before the opening bracket:

IF "%JAVAHOME%" == "" ( 
  ECHO JAVA_HOME not set
  GOTO END
)

answered May 9, 2017 at 9:55

npocmaka

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3 Comments

mahesh Over a year ago

thanks , it worked , however i see another error, "C:\Softwares\xCP\XDA_win64\xDA\bin>IF "C:\Program Files\Java\jdk1.7.0_10;" == "" ( ECHO JAVA_HOME not set GOTO END ) set was unexpected at this time.

lit Over a year ago

Please edit code and error messages into the question. It is difficult in comments.

mahesh Over a year ago

there are was ";" in the path , when i removed it worked , thanks for the help

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