I have an array:
var arr = [1,2,4,5,1,2,3,4,5];
And I have another array:
var removeArr = [1,3,5];
I want it to remove elements in arr that has in the removeArr:
var result = arr.filter(function(item){
return item != removeArr[???];
});
I have tried to iterate it using loop but it doesn't work.
You can reach the desired output using Array#filter aswell as Array#indexOf functions.
var arr = [1,2,4,5,1,2,3,4,5],
removeArr = [1,3,5],
result = arr.filter(function(item){
return removeArr.indexOf(item) == -1;
});
console.log(result);
var arr = [1,2,4,5,1,2,3,4,5];
var removeArr = [1,3,5];
var result = arr.filter(x => !removeArr.includes(x));
console.log(result);You could use a Set and test against while filtering.
var array = [1, 2, 4, 5, 1, 2, 3, 4, 5],
removeArray = [1, 3, 5],
result = array.filter((s => a => !s.has(a))(new Set(removeArray)));
console.log(result);
var result = arr.filter(function(item){
return removeArr.indexOf(item) === -1; // if the item is not included in removeArr, then return true (include it in the result array)
});
You can check if a value is in an array by checking if the index of the item is not -1.
var result = arr.filter(item => removeArr.indexOf(item) === -1)
