Laravel Pass Data to controller through ajax

Question

I'm trying to send 2 variables to FavorisController: {{ Auth::user()->id }} and the id that I have in the URL

This is what I've tried so far

Route:

Route::get('annonce_test/{id}','FavorisController@create' );

My ajax script

$(document).ready(function() {
    $('.favoris').click(function(){                  
        var id_user = "{{ Auth::user()->id }}" ;
        $.ajax({
            url: 'annonce_test/{id}',
            type: 'GET',             
            data: {id: 1, id_user: $id_user},
            success: function(data){
                alert(Ajouter au Favoris avec succes);
            },
            error: function(){},
        });""
    });         
});

FavorisController

public function create(Requests $request)
{
    $id_annonce = $_GET['id'];
    $id_user = $_GET['id_user'];
    $query = DB::table('annonce_residentiel_user')
    ->insertGetId(
        array('annonce_residentiel_id' => $id_annonce , 'user_id' => $id_user)
        );
}

I got the error trying to get property of non-object {{ Auth::user()->id }}

But is this the correct way to do it? I mean if I have another script for deleting I should chage the url in my ajax script.

Is the user logged in? If not, there is no id. Also, you have the URL incorrect in your ajax. You need to append id_user to the URL instead of using {id} — aynber
– aynber, Commented Apr 10, 2017 at 15:20
You will also need to pass the CSRF token. Docs <script> window.Laravel = {!! json_encode([ 'csrfToken' => csrf_token(), ]) !!}; </script> — dsadnick
– dsadnick, Commented Apr 10, 2017 at 15:20
Oh you're right now I can acces to the page. But it don't execute the ajax code I tried an alert but nothing shows up — Marouane Sihad
– Marouane Sihad, Commented Apr 10, 2017 at 15:33
But It's not the id_user I want in the url it's the id_annonce — Marouane Sihad
– Marouane Sihad, Commented Apr 10, 2017 at 15:37

Alexey Mezenin · Accepted Answer · 2017-04-10 15:21:49Z

1

Move Auth::user() part from JS script to PHP:

->insertGetId(['annonce_residentiel_id' => $id_annonce , 'user_id' => auth()->user()->id]);

Also, make sure user is authenticated with something like:

if (auth()->check()) {
    // Do stuff.
}

answered Apr 10, 2017 at 15:21

Alexey Mezenin

164k27 gold badges308 silver badges287 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

Marouane Sihad Over a year ago

That's correct I guess I have the error in my ajax code : data attribute

marc_s · Accepted Answer · 2017-04-11 14:21:05Z

Based on your route definition $id is the argument for the create method and to get more data from the ajax call you should use Input::get. Also the route will be activated only when the url in the ajax call has the format of ex: annonce_test/25. check the update to the ajax call.

Route:

    Route::get('annonce_test/{id}','FavorisController@create' );

Ajax call:

     $(document).ready(function() {
     $('.favoris').click(function(){                  
         var id_user = "{{ Auth::user()->id }}" ;
         $.ajax({
             url: 'annonce_test/'+id_user,
             type: 'GET',
             data: {id: 1},
             success: function(data){
                 alert(Ajouter au Favoris avec success);
             },
             error: function(){},
       });
     });         
     });

FavorisController:

    public function create($id)
    {
        $id_annonce = Input::get['id'];
        $query = DB::table('annonce_residentiel_user')->insertGetId(
          array('annonce_residentiel_id' => $id_annonce , 'user_id' => $id));
    }

Collectives™ on Stack Overflow

Laravel Pass Data to controller through ajax

2 Answers 2

1 Comment

Comments

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

1 Comment

Comments

Related