Print class type without module prefix

Question

I have a bunch of class types (derived from type). When I print them, I get stuff like:

...
<class 'Default.new_templates.NewSnippetCommand'>
<class 'Default.new_templates.NewSyntaxCommand'>
<class 'Default.pane.ClosePaneCommand'>
<class 'Default.pane.FocusNeighboringGroup'>
<class 'Default.pane.MoveToNeighboringGroup'>
<class 'Default.pane.NewPaneCommand'>
<class 'Default.pane.SetMaxColumns'>
...

I would like to print:

...
NewSnippetCommand
NewSyntaxCommand
ClosePaneCommand
FocusNeighboringGroup
MoveToNeighboringGroup
NewPaneCommand
SetMaxColumns
...

How can I get to the class name part and leave out the module part?

Dimitris Fasarakis Hilliard · Accepted Answer · 2017-03-22 17:34:58Z

5

You could use the __name__ attribute:

>>> type(OrderedDict())
<class 'collections.OrderedDict'>
>>> type(OrderedDict()).__name__
'OrderedDict'

edited Mar 22, 2017 at 17:34

answered Mar 22, 2017 at 17:30

Dimitris Fasarakis Hilliard

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2 Comments

user2357112 Over a year ago

Note that you're on IPython, which has different default display behavior from ordinary Python print or the ordinary interactive mode.

user2357112 Over a year ago

...and you just edited the input prompts to >>>, but the output behavior is still IPython behavior instead of ordinary interactive interpreter behavior.

user2357112 · Accepted Answer · 2017-03-22 17:29:48Z

3

The name of a class is the __name__ attribute:

print(whateverclass.__name__)

answered Mar 22, 2017 at 17:29

user2357112

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