My script is as follows:
# start a ubuntu container in the background
docker run -it --name ub -d ubuntu /bin/bash
sleep 1
# run a command in the container
docker exec -it ub bash
echo 234
# exit the container
exit
sleep 1
# do something else
echo 123
But the script would just stop right after exit and hang there. Does anyone know why is that?
p.s: My Docker version is: 17.03.0-ce, build 60ccb22
You have given -it during the run command. which opens up the /bin/bash of your container and waits there. The next command wont get executed until the first command execution is completed.
It's better to create a script file and move it inside the container while making the docker. and run the script on starting the docker. You may specify that using a CMD in the docker file.
You won't be needing an additional exec command.
The corresponding Dockerfile would be
FROM ubuntu:latest
COPY <path-to-script> <dest>
CMD [" <path-to-script> "]
You have to create the script file along with the Dockerfile. Build the docker using the command
docker build -t <image-name> <location of Dockerfile>
The execution command would be
docker run -d --name <name> -d ubuntu <path-to-script>
