Can't seem to understand the output of the following code snippet. trying to print the function return value in a loop
contains () {
local e
for e in "${@:2}"; do [[ "$e" == "$1" ]] && return 0; done
return 1
}
line="ayush"
line2="this is a line containing ayush"
contains $line $line2
echo $? #prints 0
for i in 1 2 3;do
contains "$line" "$line2"
echo $? #prints 1 everytime
done
@Ayush Goel
The Problem is here,
contains () {
local e
for e in "${@:2}"; do [[ "$e" == "$1" ]] && return 0; done
return 1
}
line="ayush"
line2="this is a line containing ayush"
contains $line $line2
echo $? #prints 0
for i in 1 2 3;do
contains $line $line2 # <------------------ ignore ""
echo $? # Now it will print 0
done
Difference between $var and "$var" :
1) $var case
var="this is the line"
for i in $var; do
printf $i
done
here it will print
this is the line
means $var is expanded using space
2)"$var" case
var="this is the line"
for i in "$var"; do
printf $i
done
this will print
this
here "$var" will be considered as a single argument and it will take only one value from the list.
