basic async await javascript

Question

I've got this very basic async await which I believe is not running correctly:

  const ex = {
    people: () => {console.log('people')},
    places: () => {console.log('places')}
  }


  async function example() {
    try {
      const people = await ex.people()
      const places = await ex.places()
    } catch(err) {
      console.log(err)
    }
  }
  example().then(console.log('last'))

output:

people
last
places

Shouldn't this be outputting 'people, places, last'?

Answer 1

Yes, this code snippet is pretty much ok! The only thing missing here it's that promises returns functions.

So .then should be like this:

example().then(() => console.log('last'))

Hope it works for you!

Edit:

As @gyre said, ex.people and ex.places should return promises in order to work correctly

Here's an example