shell script - How can i make multiple-read?

Question

I can not give much explanation because my English is bad. The example of what I want to do is below;

try.sh

#!/bin/sh
echo -n "Enter the port:"
read ports
if [ ! -d "$ports" ]; then

mkdir -p /root/port$ports
echo "The folder was created for $ports"
wget -q www.example.com/example.tar.bz2
tar -xjf example.tar.bz2
su root -c "screen -A -m -d -S 'example$ports' ./example -RunningAsRootIsEvilAndIKnowThat"
echo "$ports started."
else
exit 0
fi

Putty;

root@ubuntu:~# sh try.sh
Enter the port: 4445, 4546
Created folder 'port4445'
Created folder 'port4546'
4445 started.
4546 started.

How can i make?

Answer 1

#!/bin/bash
IFS=, read -p "Enter the Hosts: " -ra hosts </dev/tty
IFS=, read -p "Enter the Port: " -ra ports </dev/tty

for host in "${hosts[@]}"; do
    for port in "${ports[@]}"; do
        nc -vz $host $port
    done
done

Runtime:

bash try.sh
Enter the Port: 80
Enter the Hosts: 127.0.0.1
localhost [127.0.0.1] 80 (http) open

nc -vz $host $port will check if the $host is listening on $port

IFS=, splits input, In our case with , Think of it as input separator.

-p To display message.

-a puts input into array

Answer 2

use $* to read arguments:

 echo $* | awk '{ i=1; while(i<=NF) { print $i; i++; } }'

or

 for i in $*; do
   echo $i 
 done