Executing a command based on a variable [duplicate]

Question

I want to execute WinRAR.exe. The path of WinRAR is decided by a variable called $a. And I don't know how to correct the following code:

$a = "C:\Program Files\WinRAR"
$a\WinRAR.exe   # this line raises an error

I can see the value of echo $a:

$a = "C:\Program Files\WinRAR"
echo $a  # "C:\Program Files\WinRAR" is printed

And I'm sure that executing C:\"Program Files"\WinRAR\WinRAR.exe can launch WinRAR

Does anyone know why $a\WinRAR.exe is not working?

TechSpud · Accepted Answer · 2017-02-18 20:51:21Z

1

Really simple. You need to prefix the call to winrar with an ampersand.

&$a\winrar.exe

answered Feb 18, 2017 at 20:51

TechSpud

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