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Let's say I have a result from a query that looks like this:

ContactID     LeadSalePrice
---------------------------
   45           19.90
   45           18.00
   32           17.50

But, I want to eliminate duplicate ContactID's, always taking the higher price result. So what I want is:

ContactID     LeadSalePrice
---------------------------
   45           19.90
   32           17.50

Here's (a simplified version of) the query:

SELECT 
    sc.ContactID
    , c.LeadSalePrice
FROM
    LeadSalesCampaignCriterias c
    JOIN LeadSalesCampaigns sc ON c.LeadSalesCampaignID = sc.LeadSalesCampaignID
WHERE
    ...
ORDER BY 
    LeadSalePrice DESC

I've been playing around with DISTINCT and GROUP BY, but I'm not getting it.

1
  • Basically: SELECT ContactID, MAX(LeadSalePrice) FROM Blah GROUP BY ContactID Commented Feb 8, 2017 at 22:49

2 Answers 2

2

Just use GROUP BY:

SELECT sc.ContactID, MAX(c.LeadSalePrice) as LeadSalePrice
FROM LeadSalesCampaignCriterias c JOIN
     LeadSalesCampaigns sc
     ON c.LeadSalesCampaignID = sc.LeadSalesCampaignID
WHERE ...
GROUP BY sc.ContactID;
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1 Comment

Ah! It was the MAX() that I was missing! Thanks!
1

Another option is the WITH TIES and Row_Number()

Select Top 1 with Ties *
 From YourTable 
 Order By Row_Number() over (Partition By ContactID Order By LeadSalePrice Desc)

Returns

ContactID   LeadSalePrice
32          17.50
45          19.90

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