For loop in batch programming

Question

I have a set of files in a directory like below:

File-MyFile.txt
File-AnotherFile.txt
File-ThirdFile.txt

I want to rename all files like below:

MyFile.txt
AnotherFile.txt
ThirdFile.txt

How can I use a for loop to do that?

clifgriffin · Accepted Answer · 2010-11-16 19:50:15Z

3

Chris shows the best way to do it. I think this might come close to what you asked for, though I didn't test it:

@echo off
for /f %%a IN ('dir /b *.txt') do call :dorename %%a
goto :eof

:dorename
set oldfile=%1
set newfile=%oldfile:File-=%
rename %oldfile% %newfile%

edited Nov 16, 2010 at 19:50

answered Nov 16, 2010 at 18:51

clifgriffin

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3 Comments

clifgriffin Over a year ago

Ok, still not perfect but it does what you want it to do. YMMV.

Sathyajith Bhat Over a year ago

newfile=%oldfile:File-=% can also be newfile=%oldfile:~5%

schnaader Over a year ago

Just for completeness (this version is a bit more readable), you can use *.txt instead of dir /b *.txt and %%~nxa instead of %%a.

chris · Accepted Answer · 2010-11-16 18:49:04Z

0

you don't need a for loop:

rename File- "" File-*.txt

answered Nov 16, 2010 at 18:49

chris

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2 Comments

chanchal1987 Over a year ago

Not working for me. Showing "The syntax of the command is incorrect."

chris Over a year ago

Sorry, must have overlooked the dos-batch tag. This is for unix rename.

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