Suppose I have a constructor in c++ as:
public class Machine {
public:
Machine(int boltCount, bool failure=false);
};
How do I convert this to an equivalent class in Java?
Thanks,
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3it is not valid c++. params with defaults can only be last onesAndrey– Andrey2010-11-09 20:28:18 +00:00Commented Nov 9, 2010 at 20:28
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Really? Besides the obvious problem pointed out by Andrey, it is simply a class declaration and a constructor. Java does not support default argument values, so you will have to use constructor chaining.Ed Swangren– Ed Swangren2010-11-09 20:30:27 +00:00Commented Nov 9, 2010 at 20:30
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1This is not valid C++: there are no public classes, and the parameters with default values must be rightmost. So it's not clear what it actually is that you want an equivalent for.Martin v. Löwis– Martin v. Löwis2010-11-09 20:30:30 +00:00Commented Nov 9, 2010 at 20:30
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"public class XXX" is valid C++?? When did that happen?Edward Strange– Edward Strange2010-11-09 20:30:47 +00:00Commented Nov 9, 2010 at 20:30
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@Noah: When Sun bought MicroSoft and took over the world.John Dibling– John Dibling2010-11-09 20:42:51 +00:00Commented Nov 9, 2010 at 20:42
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2 Answers
something like that
public class Machine {
public Machine(int boltCount) { this(boltCount, false); }
public Machine(int boltCount, bool failure) { /*body here*/ }
};
3 Comments
Neel
Ahh! Got it.. There is a constructor explosion but I think this works.. Thanks!
Andrey
i want to add that C# 4.0 has optional parameters! (trying to make java developers switch to c# :)
Neel
I mean for each c++ constructor with one default value set, this gives rise to 2x Java constructors.
You would have to use constructor chaining, as Java does not have default values for parameters:
public class Machine {
Machine(int boltCount) {
this(boltCount, false);
}
Machine(int boltCount, boolean failure) {
// constructor logic
}
}
