I have this following function, where Math.max() is not working as expected. It is always alerting the 1st value from the arguments that are passing. Where is the mistake?
function large(arr) {
alert(Math.max(arr))
}
large(1,2,3,4,5);
2 Answers
You are passing multiple arguments, but your function only uses the first one.
In ES5 and before, you can use the apply method of a function and the arguments object:
function large() {
alert(Math.max.apply(Math, arguments))
}
large(1,2,3,4,5);In ES6 you can use the rest and spread operator:
function large(...arr) {
alert(Math.max(...arr))
}
large(1,2,3,4,5);
answered Dec 19, 2016 at 5:12
Alexander O'Mara
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5 Comments
Alexander O'Mara
@Mahi It allows you to call a function with an array (or array-like object) of arguments, with an unknown length.
Walf
Should probably specify that it's
Function.prototype.apply() in use, here.Alexander O'Mara
@Walf Sure thing.
nnnnnn
Note that you're using rest parameter syntax as well as the spread operator.
Alexander O'Mara
@nnnnnn Very true.
You can do like this.
If you want to use the arguments you can avoid the parameter of the function. Then use the apply function to call Math.max
function large() {
var _max = Math.max.apply(Math, arguments);
alert(_max)
};
large(1, 2, 3, 4, 5, 20,9000);
arrto the first argument. The other argument values are only accessible through theargumentskeyword.