Replace with SED multiple occurences at the same line

Question

I want to replace all slashes "/" between alphanumeric with backslash+slash "\/" apart from the last one on each string, e.g.

nocareNocare abc\/def/ghi/mno\/pq/r   abc\/def\/ghi/mno\/pq/r

should become:

nocareNocare abc\/def\/ghi\/mno\/pq/r   abc\/def\/ghi\/mno\/pq/r

I use:

sed 's/\(.*\)\([[:alnum:]]\)\/\([[:alnum:]]\)\(\S*\)\(\\\|\/\)/\1\2\\\/\3\4\//g'

Short explanation: match

any string + alnum + / + any non-white + / or \

But it only replace one case, so I need to run it 3 times to replace all 3 occurences. Looks like the first time it matches all the way to :

>nocareNocare abc\/def/ghi/mno\/pq/r   abc\/def\/ghi/

instead of

>nocareNocare abc\/def/

Answer 1

sed -e :a -e 's|\([a-z0-9]\)/\([a-z0-9][^ ]*[a-z0-9]/[a-z0-9]\)|\1\\/\2|;ta' filename

Loosely translated, this says "replace a lone slash followed by some other stuff in the string, followed by another lone slash, with backslash-slash and that same stuff (and the second slash). And after making such a replacement, start over again."

Answer 2

You can use a perl command line solution based on the following regEx's

(?<!\\)

not preceded by a backslash

(?!\w+\s)

not followed by word characters terminating in whitespace

perl -pe 's;(?<!\\)/(?!\w+\s);\\/;g' file
nocareNocare abc\/def\/ghi\/mno\/pq/r   abc\/def\/ghi\/mno\/pq/r

Answer 3

With GNU sed:

sed -E 's:([^\])/:\1\\/:g;s:\\/([^\]*( |$)):/\1:g' file

Two s command here:

• s:([^\])/:\1\\/:g replace all / not preceded by a \ with \/
• s:\\/([^\]*( |$)):/\1:g replace last \/ before space or end of line with /