How to get everything from the list except the first element using list slicing [duplicate]

Question

I want to parse something like:

list = ['A', 'B', 'C']

And using list slicing have it return to me everything but the first index:

['B', 'C']

I tried list[:-1], list[::-1], list[0:-1], etc.

What I am doing:

I have a error message that has an error code in the beginning such as:

['226', 'Transfer', 'Complete'] and I want to just display Transfer Complete on a popup widget. I am casting to a string.

If answer differs via Python 2.7.x and Python 3.x.x, please answer for both versions.

@cricket_007 is that an alternative of doing .split( " ") [1:]? — Omid CompSCI
– Omid CompSCI, Commented Nov 5, 2016 at 21:25
Split returns a list. Slicing returns a list. String Joining returns a string, so no, it's the inverse, not alternative — OneCricketeer
– OneCricketeer, Commented Nov 5, 2016 at 21:29

user7111497user7111497 · Accepted Answer · 2016-11-05 21:22:36Z

178

You can just do [1:]. This will work on both versions.

answered Nov 5, 2016 at 21:22

user7111497

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Comments

pzp · Accepted Answer · 2016-11-06 04:40:33Z

61

It can be done like this:

list[1:]

pzp

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answered Nov 5, 2016 at 21:23

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