swift struct as function parameter

Question

I have a struct/model that I store some JSON data to fill my tableview:

import SwiftyJSON

struct MyData {

    let valOne: Int
    let valTwo: String
    let valThree: Int

    init(json: JSON) {
        valOne = json["some_data"].intValue
        valTwo = json["auc_data"].stringValue
        valThree = json["auc_data"].intValue
    }
}

Then in my tableview I have a custom cell class that I use when I write out my data:

let data = MyData[indexPath.row]

let cell = tableView.dequeueReusableCell(withIdentifier: "myCell") as! CustomTableViewCell

cell.configureCellWithData(data)

What I want to do is to pass the struct as a parameter to the configureCellWithData() but I am not sure how to declare it.

Instead of doing something like:

func configureCellWithData(dataOne: Int, dataTwo: String, dataThree: Int) {

}

then

configureCellWithData(data.valOne,data.valTwo,data.valThree)

I dont want to have many parameters instead I want to send the struct right away

Have you tried this way ? func configureCellWithData(data: MyData) { } — Muzahid
– Muzahid, Commented Oct 20, 2016 at 2:44
The let data = MyData[indexPath.row] line doesn't make sense. I assume you have some property defined like var dataObjects = [MyData]() or something like that, and you'd then do let data = dataObjects[indexPath.row]. — Rob
– Rob, Commented Oct 20, 2016 at 2:55

hooliooo · Accepted Answer · 2016-10-20 02:44:37Z

5

Try this.

func configureCellWith(data: MyData) {
    // Do stuff here
}

answered Oct 20, 2016 at 2:44

hooliooo

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1 Comment

Rob Over a year ago

Yep, or if Swift 3, perhaps func configureCell(with data: MyData) { ... }.

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