Release notes from git log using bash awk

Question

We follow a commit message policy that allows us to parse git log for release notes.

[category US123] Description of what is changed

eg:

[feature US123] Added the version number to the meta:version tag of every page. Better for support.
[dev US123] remove development entries before production
[settings US123] New STS webservice url for UAT

The bash script below parses the log, but there's a trailing number after each user story / defect.

Is this a side effect of awk? What needs to change to remove the trailing number?

git log -100 --pretty="%s" | grep -io "$DE\|US$[0-9]\{3,\}" | sort | uniq | awk '{print $1; print system("git log --pretty=\"%cI %an %s\" | grep -i -v \"Merge\" | grep -i "$1)}'

that is probably because of system function you called inside awk. This could be done in some other way if you provide sample input text and desired output data. — P....
– P...., Commented Oct 6, 2016 at 7:02

qzb · Accepted Answer · 2016-10-06 07:58:29Z

2

You have to replace print system(...) with just system(...):

git log -100 --pretty="%s" | grep -io "\(DE\|US\)[0-9]\{3,\}" | sort | uniq | awk '{print $1; system("git log --pretty=\"%cI %an %s\" | grep -i -v \"Merge\" | grep -i "$1)}'

system() function prints to stdout by itself, when you call print system(...) you actually print exit code returned by system().

answered Oct 6, 2016 at 7:58

qzb

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1 Comment

Joshua Over a year ago

Thanks! That nailed it.

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