So far I have this code:
def find_words(m_count, m_string):
m_list = re.findall(r'\w{6,}', m_string)
return m_list
is there a way to use m_count instead of using the count number (6) explicitly??
asked Aug 19, 2016 at 16:07
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3 Answers
Convert the int to string and added to you reg exp like this:
def find_words(m_count, m_string):
m_list = re.findall(r'\w{'+str(m_count)+',}', m_string)
return m_list
1 Comment
anubhava
If you notice I had same answer posted 5-6 minutes ago :)
You can build a regex by concatenating your count variable and static part like this:
>>> m_count = 6
>>> re.findall(r'\w{' + str(m_count) + ',}', 'abcdefg 1234 124xyz')
['abcdefg', '124xyz']
answered Aug 19, 2016 at 16:11
1 Comment
a fair player
For those who might be using PyCharm, if you face "pattern expected" error, you can define the pattern on a different line (pattern = r'\w{' + str(m_count) + ',}') and then use the pattern directly (re.findall(pattern, 'abcdefg 1234 124xyz'))
You can use format(), and escape the curly braces.
>>> import re
>>> m_count = 6
>>> print re.findall(r'\w{{{},}}'.format(m_count),'123456789 foobar hello_world')
['123456789', 'hello_world']
Full method body:
def find_words(m_count, m_string):
m_list = re.findall(r'\w{{{},}}'.format(m_count), m_string)
return m_list
