Get command output into variable

Question

In bash I got all the names from services which are balanced from /etc/haproxy. But now I want to store all these intro a $srv variable in order to continue my healthcheck script.

for filename in /etc/haproxy/*.cfg; do
    for ((i=0; i<=0; i++)); do
      srv = $(echo $filename | awk -F'[/.]' '{print $4}')
      echo $srv
    done
done

Using echo $filename | awk -F'[/.]' '{print $4}' is showing the correct microservices names like: service1 service2 service3

Change line-3: to srv="$(echo "$filename" | awk -F'[/.]' '{print $4}')" — Inian
– Inian, Commented Aug 1, 2016 at 9:27

Barmar · Accepted Answer · 2016-08-01 09:28:14Z

2

You can't have spaces around the = in shell variable assignments. What you wrote is trying to run the srv command, not assign to the srv variable. It should be:

srv=$(echo $filename | awk -F'[/.]' '{print $4}')

answered Aug 1, 2016 at 9:28

Barmar

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2 Comments

Barmar Over a year ago

How do you learn shell scripting without such basic information?

Vlad Cenan Over a year ago

I use only chef and ruby. But apparently there are VMs were you cannot set ruby environments and you have to deal with bash:) Last time I got blocked at the exact same step but I found a way around with some percona healthchecks. Thanks again!

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