Is there a method or way to read and keep reading chars from a string, putting them in a new string until there is a certain char. Keep reading from < to > but no further. Thankx
3 Answers
Of course. You will need:
- the method
String.charAt(int) - the
+operator (or the methodString.concat, or, if performance matters, the classStringBuilder) - the
forstatement - and perhaps an
if-statement with abreakstatement
The statements and operators are explained in the Java Tutorial, and the method in the api javadoc.
(And no, I will not provide an implementation, since you would learn little by copying it)
Comments
You can actually write a utility that does that
public class StringUtil {
public static String copy(String str, char startChar, char endChar) {
int startPos = str.indexOf(startChar);
int endPos = str.lastIndexOf(endChar);
if (endPos < startPos) {
throw new RuntimeException("endPos < startPos");
}
char[] dest = new char[endPos - startPos + 1];
str.getChars(startPos, endPos, dest, 0);
return new String(dest);
}
};
PS Untested....
Alternatively, you can
String result = str.substring(startPos, endPos + 1); //If you want to include the ">" tag.
3 Comments
Powerlord
You had me up until the
char[] line. That line and the ones afterward seem like an awful lot of work for recreating String.substring.
BalusC
And,
lastIndexOf() may not be what you need. This will fail on e.g. text<foo>text</foo>text and return <foo>text</foo> instead of <foo>.
Buhake Sindi
@BalusC, agreed, the SO can use
str.indexOf(endChar, startPos + 1) to find the closest closing bracket. I'm assuming that str = "<foo>"This may not be what you want but it will give you the desired string.
String desiredString="<Hello>".split("[<>]")[1];
<to>? Aren't you reinventing a XML/HTML parser?