taking difference of array with specific spacing in numpy

Question

I'm approximating a first order derivative of an array in numpy using np.ediff1d:

x=array([ 1,  2,  5, 10])
np.ediff1d(x) # = array([1, 3, 5])

np.ediff1d uses consecutive elements of the array. Is there a way to control the spacing i.e. is there a numpy function that calculates the difference between every n-th element, as sliding window?

example: newdiff(x, window=2) would be: [5-1, 10-2] or [4, 8].

Tim Hoffmann · Accepted Answer · 2016-05-31 02:03:39Z

5

Simply take the difference of shifted slices:

n = 2
x[n:] - x[:-n]

answered May 31, 2016 at 2:03

Tim Hoffmann

1,3559 silver badges30 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

2342G456DI8 · Accepted Answer · 2016-05-31 02:25:02Z

2

n=2
v = [x[i+n]-x[i] for i in range(len(x)-n)]

answered May 31, 2016 at 2:25

2342G456DI8

1,8093 gold badges17 silver badges29 bronze badges

Collectives™ on Stack Overflow

taking difference of array with specific spacing in numpy

2 Answers 2

Comments

Comments

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Related