array pointers in c++

Question

How do you access/dereference with arrays in c++??

for example, if I have this code

int num[] = {0,1,2,3};
int *p = &num;

I thought p was point to the first element in num array?

For some reason, I get a compiler error.

I want to use pointers and increments to access and change the value that is pointing,

for example, p gets the address of the first variable in the int array num and if I increment p, I get the address of the second variable in the int array num.

Any tips would be appreciate it.

@kjpus: actually, the type of &num is int (*) [4]. The sizeof and & operators have special meaning for array types. — dreamlax
– dreamlax, Commented Apr 27, 2016 at 2:51
@dreamlax actually they have the same meaning for all types; it is the array types which have special meaning in other contexts — M.M
– M.M, Commented Apr 27, 2016 at 2:52

Remy Lebeau · Accepted Answer · 2016-04-27 02:49:08Z

8

I thought p was point to the first element in num array?

No. int *p = &num; is wrong, since &num is not a pointer to an int, i.e. int*, but is actually a pointer to an array of ints, i.e. int (*) [4].

To get a pointer to the first element, you can use int *p = num;, or int *p = &num[0]; instead.

edited Apr 27, 2016 at 2:49

Remy Lebeau

609k36 gold badges516 silver badges873 bronze badges

answered Apr 27, 2016 at 2:37

songyuanyao

173k16 gold badges327 silver badges432 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

array pointers in c++

1 Answer 1

Comments

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Related