Angular Extracting Operators

Question

I want to write some code to parse a search string. My previous post shows my filter code thanks to Scraph. Now I need to handle the following search scenarios:

age>10
age>=10
items!=3

The following code detects if there's a number in the string:

if(queryValue.match(/\d+/g)) {
   $log.debug("Regex detected numbers");
}

I've tested this and it works with an input like >=10. Now I need to extract the >= and apply that to my search. I can create an array or operators like so:

var operators = ['>', '>=', '<', '<=', "!="]

And then have a for loop to figure out which operator it is then extract the number portion and do the filtering. However that seems overly verbose so I'm wondering if there's a cleaner solution to my problem.

Maybe dumb comment, but... w3schools.com/jsref/jsref_eval.asp ? — Christian Bonato
– Christian Bonato, Commented Apr 21, 2016 at 1:14
It is unclear what exactly you need. Please show what you want to achieve with a regex. — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Apr 21, 2016 at 6:19

rock321987 · Accepted Answer · 2016-04-21 10:29:13Z

1

Assuming only the 5 mentioned cases above, the following will work

[><]=?|!=

Regex Demo

JS Demo (not Angular JS)

var re = /([><]=?|!=)/; 
var str = ['>=', '<=', '=', '!=', '<', '>', '!', 'abc>=234'];

str.forEach(function(number) {
  if (number.match(re))
      document.writeln(number.match(re)[1] + '<br>');
});

Angular JS Demo

edited Apr 21, 2016 at 10:29

answered Apr 21, 2016 at 3:04

rock321987

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