Is it possible to create multiple classes from a list, like this:
for cn in ['ABC', 'DEF', 'GHI']:
class {cn.capitalize()?}(Base):
__mapper_args__ = {
'polymorphic_identity': cn.lower(),
}
Note: In all questions I found with a similar title, questioners actually wanted to create multiple objects from a single class
You could create new class at runtime using type:
In [17]: class_names = ['ABC', 'DEF', 'GHI']
In [18]: classes = {name: type(name.capitalize(), (Base,),
{'__mapper_args__': {'polymorphic_identity': name.lower()}})
for name in class_names}
In [19]: classes['DEF']
Out[19]: __main__.Def
In [20]: classes['ABC']().__mapper_args__
Out[20]: {'polymorphic_identity': 'abc'}
In [21]: import inspect
In [22]: inspect.getmro(classes['GHI'])
Out[22]: (__main__.Ghi, __main__.Base, object)
[name for name, obj in inspect.getmembers(sys.modules[__name__]) if inspect.isclass(obj)]
globals() dictionary, although, I don't know if SQLAlchemy be able to use them. See this answer for details: stackoverflow.com/a/5036827/1532460type as described in the answer, and then add them into gloabals().