I have apache and Node.js running on Ubuntu
Is there a way to programatically check if the apache service is running with Node? If it's not running, allow Node.js to start/restart the service, also could the same code be used to run other processes like MySQL?
I'd also like to find a way to make Node execute "ps -u user" and capture the output in a js string or object
I've had a look at Node.js child processes but I can't figure it out
Thanks in advance
You can use the "exec" method of "child_process" module to execute a command from your node app and have its output passed as a parameter to a callback function.
var exec = require("child_process").exec;
exec("ps -u user", function (error, stdout, stderr) {
var myResult = stdout;
//doSomething
});
You could also use shelljs - https://www.npmjs.com/package/shelljs, which has many functions goes directly to shell and is cross-platform. ps command is not one of them, so use exec similar as with child_process.
require('shelljs/global');
exec('ps -aux | grep apache')
With exec you could start/restart service too, however you will need to run node process as root, what's not best option. Or create usergroup specifically for apache.
To run 'ps -u user' use the same. It will return you object with all info you need about processes.
exec('ps -u user');
And than continue with output as you need.
with spawn you can run shell scripts. So if you had a shell script written to check if a processes is running...something like this you should us spawn to run it. something like...
var child = spawn('sh', [__dirname+'/some-status-shell-script.sh'], {env: process.env});
Likewise you can use spawn to access your mysql db...similiar to this
